My writing is easy to understand, just look at you and you will understand. For example.
An example of RSA algorithm is given.
/lsgo/blog/item/5fd 0 da 24d 495666834 a 80 FB 8 . html
There seems to be an algorithm in space.
I know I just answered another friend's question and posted it for you to see.
/question/9 126 1774 . html? si=2
Title: When using RSA algorithm to encrypt, the public key is (e=7, n=20) and the private key is (e=3, n=20). When the message M=3 is encrypted with the public key, the ciphertext obtained is _ _ _ _ _?
Give the detailed process. thank you
A:
What you said:
n=20
D=7 public key
E=3 private key
Encryption M=3.
M' = m d% n (m to the power of d, and then divide by n to take the remainder)
M' = 3 7% 20 = 2 187% 20 = 7 after encryption, it is equal to 7.
Decryption M'=7.
M = m 'e% n = 7.3% 20 = 34.3% 20 = 3. After decryption, it became 3 again.
The two prime numbers you take are too small, so n is too small to work at all. Take at least 1024 digits.