The calculation is as follows:
The probability that the first A is in your enemy's hands is 2/3 (because two out of three people are your enemies), and the probability that the second A is in his hands is 1/3
, so the probability of being caught by A pair is 2/3 * 1/3 = 2/9
. Those who don't get caught =7/9
The total probability of being caught is to use the senior three probability formula =1- the probability of not being caught by any big pair at the same time
= 1-7/9 * 7/9 * 7/9 = 63.4%
It's quite dangerous indeed. But note that this is not a probability. You don't calculate the details of catching eight more cards and matching one card for yourself. The answer is approximate, but it has little effect on the answer, and you can see that you don't need to be so precise.
because the calculation is very simple, it's shown today, so I'll forget the rest with you!
if you have one in A, K, Q and J, the probability of being caught in 1 pairs is 52.95%
if you have two in A, K, Q and J, the probability of being caught in 1 pairs is 39.51%
if you have three in A, K, Q and J, the probability of being caught in 1 pairs is = ! ! ...