1, F float =p water gV row = 1.0× 10? kg/m？ * 10N/kg*0.8m？ =8000N2, when the assault boat is fully loaded, the following requirements should be met: F float =G-n(G people wear G clothes), so the maximum number of people that can be carried: n=(F float -G)/(G people wear G clothes) = (8000n-2500n)/(600n1. 3, ∫ people float, f float =G people g clothes, f float = ρ water gv platoon, 1.0× 10? kg/m？ * 10N/kg×(0.06m？ -0.004m？ V clothes) =600N 10Nv clothes =0.005m? Material density of life jacket: ρ clothing =m clothing /v clothing = [10n/(10n/kg)]/0.005m? =0.2× 10? kg/m？ Answer: (1) The buoyancy of the assault boat is 8000 N when the displacement reaches the maximum; (2) The assault boat can carry up to 9 soldiers wearing life jackets; (3) The maximum density of life jacket material is 0.2× 10? kg/m？