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I am a gambler in A Chinese Odyssey 2. How to calculate the number of enemies I met? Know which one will be more and which one will be less? Do you know that the master teaches gambling skills?
Let me show you how to calculate this. First of all, guessing big is the same as guessing small.

The number of strange things in a team of two people is 2, 3, 4, 5, 6, and the probability is 20%. Consider guessing the big picture.

Count two first.

The better chance of two brothers is 25%, the better chance of two scorpions is 25%, and the same chance of one of them is 50%.

Considering that the probability of meeting two monsters is 20%, do a multiplication of 20%*25%=5%.

The situation of three

12.5% probability 3 brothers 37.5%2 brothers 1 scorpion 37.5% 1 brother 2 scorpions 12.5%3 scorpions also have a big guess probability of 20%*50%= 10%.

Four situations

I won't write the specific calculation. The probability is 20%*5/ 16=6.25%.

Five cases are 10%

6 situation 5%

So the total probability is 5+10+6.25+10+5 = 36.25%.

Haha, so many people do business, and you often lose. Even if he calls for a five-combo, the chance of hitting a five-combo is almost impossible, and the chance of hitting an eight-combo is less than three ten thousandths.

How was the answer?