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As shown in the figure, in the parallelogram ABCD, P 1 P2 P3 P4 P5 P6 P7 is the bisector of diagonal BD. Can you choose two of these seven bisectors?
Yes, the intersection connecting AC, AC and BD is P4. Take quadrilateral AP5CP3 as an example.

Because AP4=CP4, P5P4=P3P4.

According to one of the judging theorems of parallelogram, quadrilaterals whose diagonals bisect each other are parallelograms.

The quadrilateral AP5CP3 is a parallelogram.

Similarly, it can be proved that quadrilateral AP6CP2 and quadrilateral AP7CP 1 are also parallelograms.

hope this helps