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What is the quadratic equation ax·2+bx+c=0 equal to X1+X2? Ask for the proof process (the one with the signature is the

In fact, it is Vedic Theorem

x1+x2=-b/a

The proof process is the proof process of Vedic Theorem,

The formula for finding the root of a quadratic equation of one variable is:

X1= (-b+√b^2-4ac)/2a, X2= (-b-√b^2-4ac)/2a 

X1﹢X2= (-ab+ 2a-4ac)/2a+(-b-√b^2-4ac)/2a 

So X1﹢X2=-b/a

X1X2= [(-b+√b ^2-4ac﹚÷2a]×[(-b-√b^2-4ac﹚÷2a] 

So X1X2=c/a